Answer: [tex]x\geq\dfrac{38}{9}[/tex]
Step-by-step explanation:
The given inequality : [tex]58 - 10x \leq 20 + 9x[/tex]
To solve the given inequality , we first add 10x on both the sides , we get
[tex]58-10x+10x\leq20+9x+10x\\\\\Rightarrow\ 58\leq20+19x[/tex]
Subtract 20 on both the sides , we get
[tex]58-20\leq20+9x-20\\\\\Rightarrow\ 38\leq9x\text{ or }9x\geq38[/tex]
Then, divide 9 on both sides , we get
[tex]x\geq\dfrac{38}{9}[/tex]
Hence, the solution of the given inequality will be [tex]x\geq\dfrac{38}{9}[/tex]
