Explanation:
Given that,
First mass, [tex]m_1=12\ Mg[/tex]
Other mass, [tex]m_2=12\ g[/tex]
We know that,
1 Megagram (Mg) = 10⁶ grams (g)
So, [tex]1\ g=10^{-6}\ Mg[/tex]
Using unitary method,
[tex]m_2=12\ g=12\times 10^{-6}\ Mg[/tex]
So, [tex]m_1-m_2=12\ Mg-12\times 10^{-6}\ Mg[/tex]
[tex]m_1-m_2=10^{-6}[/tex]
So, the mass of 12 Mg is [tex]10^{-6}[/tex] more than 12 grams. Hence, this is the required solution.
