Answer:
[tex]3.5 \frac{m}{s^{2} }[/tex]
Explanation:
Hello.
The acceleration is the change of speed in a time elapsed from point A to B
[tex]a=\frac{V_{f} -V_{i} }{t_{2}-t_{1}}[/tex]
step 1
position 1
[tex]velocity: 2.0\frac{m}{s}\\ time : t_{1}[/tex]
position 2
[tex]velocity: 44.0\frac{m}{s}\\ time : t_{1} +12 =t_{2}\\[/tex]
step 2
replace
[tex]a=\frac{V_{f} -V_{i} }{t_{2}-t_{1}}\\\\a=\frac{44-2}{t_{2}-t_{1} }=\frac{44-2}{t_{1}+12-t_{1} }\\a=\frac{42\frac{m}{s} }{12 s} }\\a=3.5\frac{m}{s^{2} }[/tex]
the acceleration of the rock is
[tex]3.5 \frac{m}{s^{2} }[/tex]
I hope it helps.
