Respuesta :
EF + FG = EG
2x-12+3x-15=23
5x=50
x=10
EF=2(10)-12=8
FG=3(10)-15=15
2x-12+3x-15=23
5x=50
x=10
EF=2(10)-12=8
FG=3(10)-15=15
Answer:
By the segment addition postulate:
If F is on segment EG, then [tex]EF+FG = EG[/tex]
As per the statement:
If EF = 4x − 16, FG = 3x − 6, and EG = 27
then by above definition we have;
[tex]EF+FG = EG[/tex]
[tex]4x-16+3x-6 = 27[/tex]
Combine like terms;
[tex]7x-22= 27[/tex]
Add 22 to both sides we have;
[tex]7x=49[/tex]
Divide both sides by 7 we have;
x = 7
EF = 4x-16 = 4(7)-16 = 28-16 = 12
FG = 3x-6 = 3(7)-6 = 21-6 = 15
Therefore, the values are x = 7, EF = 12 and FG = 15.
