Respuesta :

The rule is [tex]a \sqrt{b}+c \sqrt{b}=(a+c) \sqrt{b} [/tex], so

[tex]4 \sqrt{5}+2 \sqrt{5} = 6 \sqrt{5} [/tex]

Answer:

[tex]6\sqrt{5}[/tex]

Step-by-step explanation:

sum of 4 sqrt 5 + 2 sqrt 5

[tex]4\sqrt{5} + 2\sqrt{5}[/tex]

Both terms have same square root(5)

So they are like terms.

When they are like terms, we add the number outside the square root.

Square root remains the same.

[tex]a\sqrt{x} + b\sqrt{x}=(a+b)\sqrt{x} [/tex]

[tex]4\sqrt{5} + 2\sqrt{5}=(4+2)\sqrt{5}=6\sqrt{5}[/tex]