Respuesta :
Let's say the first integer is n. the next two integers will be n+1 and n+2. If you add these three together you will get n+n+1+n+2, which is 3n+3
so,
3n+3=135
3n=132
n= 44
thus, the first integer is 44. the next two consecutive will thus be 45 and 46
to check: 44+45+46=135
and there you have your answer, hope I helped!
so,
3n+3=135
3n=132
n= 44
thus, the first integer is 44. the next two consecutive will thus be 45 and 46
to check: 44+45+46=135
and there you have your answer, hope I helped!
Three consecutive integers can be represented as followed.
X → first integer
X + 1 → second integer
X + 2 → third integer
Since the sum of our three consecutive integers is 135, we can set up an equation to represent this.
X + X + 1 + X + 2 = 135
-Simplify on the left-
3x + 3 = 135
-3 -3
3x = 132
÷3 ÷3 ← divide both sides by 3
X = 44
X + 1 = 45
X + 2 = 46
Therefore, the three consecutive integers are 44, 45, and 46.