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CollinStanley
 If i'm not mistaken the ratio is between Ca(OH)2 and HCl in the balanced equation 

Ca(OH)2 + 2 HCl = CaCl2 + 2 H2O 

is 1 : 2 

moles HCl required = 0.30 x 2 = 0.60

So, the answer should be: B) 0.60 moles

♦Brainliest Please♦

Answer: The moles of HCl required to completely neutralize calcium hydroxide is 0.60 moles.

Explanation:

We are given:

Moles of calcium hydroxide = 0.30 moles

The chemical equation for the reaction of HCl with calcium hydroxide follows:

[tex]Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O[/tex]

By Stoichiometry of the reaction:

1 mole of calcium hydroxide reacts with 2 moles of HCl

So, 0.30 moles of calcium hydroxide will react with = [tex]\frac{2}{1}\times 0.30=0.60mol[/tex] of HCl

Hence, the moles of HCl required to completely neutralize calcium hydroxide is 0.60 moles.

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