In a direct variation relationship the values must satisfy that y = kx. This si y is always a constant value (k) times x.
So, you can find multiple values that meet this:
y = kx => k = y / x = 11 / 18
=> y = (11/18)x
Now you can give any value to x and fint the value of x that satisfy the relationship:
x y = (11/18)x
1 11/18
2 11/18 * 2 = 11/9
18 11/18 * 18 = 11
36 11/18 * 36 = 22
So, there you have several additional values for x and y in the same relationship that y = 11 and x = 18, and you can find many more using the same rule: y = (11/18)*x
