You lose one quarter, two dimes, and two nickels.
a. write the amount as a decimal.
b. write the amount as a fraction in simplest form

Respuesta :

To answer this question you need to know how much is a quarter($0.25), a dime($0.10) and nickel($0.05) worth. Then, the total money he lose would be:

1($0.25) + 2($0.10) + 2($0.05)= $0.25 + $0.20 + $0.10= $0.45

The decimal form would be $0.45
The fraction form would be (45/100) / (5/5)= 9/20

You lose one quarter, two dimes, and two nickels.

1 quarter = 25 cents= 0.25 dollars

1 dime = 10 cents = 0.10 dollars

1 nickels = 5 cents= 0.05 dollars

2 dimes = 0.10 *2 = 0.20 dollars

2 nickels = 0.05 * 2= 0.10 dollars

Total money he lose = one quarter+ two dimes + and two nickels

= 0.25 + 0.20 + 0.10 = 0.55 dollars

The decimal form is 0.55

We can write 0.55 as [tex]\frac{55}{100}[/tex]

then we reduce the fraction by dividing both numerator and denominator by 5

[tex]\frac{\frac55}{\frac{100}{5}}}[/tex] = [tex]\frac{11}{20}[/tex]

The fraction form is [tex]\frac{11}{20}[/tex]