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sulfur dioxide gas reacts with oxygen gas and water according to the chemical reaction below. when 4.5 g of SO2 are mixed with excess O2 and H2O, how many grams of H2SO4 are produced

Respuesta :

2H2O + 2SO2 + O2 ----> 2H2SO4

using the molar masses :-

2*(32+32) SO2  produces 2*(2+ 32 + 64) g of H2SO4

128   gives 196 g

4.5 g SO2  produces   (196* 4.5) / 128  = 6.89 g H2SO4  Answer
Eduard22sly

The mass in grams of H₂SO₄ produced from the reaction when 4.5 g of SO₂ reacts is 6.89 g

Balanced equation

2SO₂ + O₂ + 2H₂O —> 2H₂SO₄

Molar mass of SO₂ = 64 g/mole

Mass of SO₂ from the balanced equation = 2 × 64 = 128 g

Molar mass of H₂SO₄ = 98 g/mole

Mass of H₂SO₄ from the balanced equation = 2 × 98 = 196 g

SUMMARY

From the balanced equation above,

128 g of SO₂ reacted to produce 196 g of H₂SO₄

How to determine the mass of H₂SO₄ produced

From the balanced equation above,

128 g of SO₂ reacted to produce 196 g of H₂SO₄

Therefore,

4.5 g of SO₂ will react to produce = (4.5 × 196) / 128 = 6.89 g of H₂SO₄

Thus, 6.89 g of H₂SO₄ were obtained from the reaction

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