Alright, so what you would do is find the y intercepts of each function - make y=0, and solve it for each equation. If the y intercepts for 2x-3=y and x+4=y overlap with the y intercepts for y=2x^2+5x-12, it's right. For graphing the last two equations, you can simply plug in random values of x and get the output of y (for example, in x+4 you can plug in x=1 to get 1+4=5=y, getting (1,5) as one point) and in the same equation you can get 2 points and connect the dots. However, it's a bit different for 2x^2+5x-12 - you have to find the x value of the vertex (-b/2a=-5/4 in ax^2+bx+c) and plug it into the equation to get the y value. After that, you plug in one value greater than the x value of the vertex and one value smaller. Lastly, you connect it in kind of a U shape
