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How much work is required to move
3.0 coulombs of electric charge a distance of
0.010 meter through a potential difference of
9.0 volts?
(1) 2.7 × 10^3 J (3) 3.0 J
(2) 27 J (4) 3.0 × 10^−2 J

Respuesta :

Hippalectryon
The work is path independent since we have a conservative force.

Thus [tex]W=d\cdot\frac{q\cdot U}{d^2}=\frac{3.0\cdot9.0}{0.010}=\boxed{2700 J}[/tex]

Answer (1)

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