Answer:
In a 0.925 M KNO3 solution with a volume of 925.0 ml, the calculation to determine the grams of KNO3 involves several steps. Initially, the volume must be converted from milliliters to liters, yielding 0.925 liters. The molar mass of KNO3 (potassium nitrate) is then calculated by summing the atomic masses of its constituent elements: potassium (K), nitrogen (N), and oxygen (O). This yields a molar mass of 101.10 g/mol for KNO3. Utilizing the formula for calculating grams of solute in a solution, which involves multiplying molarity by volume in liters by molar mass, we find that the solution contains 85.5 grams of KNO3. This result provides a quantitative understanding of the concentration of KNO3 within the given solution, facilitating precise measurements and adjustments in chemical processes or experiments where this solution is employed.
So, there are 85.5 grams of KNO3 in 925.0 ml of a 0.925 M KNO3 solution.
