contestada

A box of mass 63g is attached to a horizontal spring with spring constant 102N/m. The spring is then extended by 10 cm, and the box is subsequently released. Calculate the speed of the box, assuming the entire elastic potential energy is converted to the box's kinetic energy. Give your answer to 2 decimal places if needed

Respuesta :

MathPhys

Answer:

4.02 m/s

Explanation:

Elastic potential energy is half the spring constant times the square of the displacement. Kinetic energy is half the mass times the square of the speed.

EE = KE

½ kx² = ½ mv²

kx² = mv²

v = x √(k / m)

v = (0.10 m) √(102 N/m / 0.063 kg)

v = 4.02 m/s

Otras preguntas