Answer:
To calculate the current flowing through the LED light bulb, we can use the formula:
\[ P = VI \]
where:
- \( P \) is the power (in watts),
- \( V \) is the voltage (in volts), and
- \( I \) is the current (in amperes).
Given that the power of the LED light bulb is \( P = 3.9 \) W and the voltage of the outlet is \( V = 120 \) V, we can rearrange the formula to solve for the current \( I \):
\[ I = \frac{P}{V} \]
\[ I = \frac{3.9 \, \text{W}}{120 \, \text{V}} \]
\[ I = \frac{3.9}{120} \, \text{A} \]
\[ I \approx 0.033 \, \text{A} \]
So, the current flowing through the LED light bulb is approximately \( 0.033 \, \text{A} \).
