Given rectangle ABCD , find X and m∠BCA.

Answer: x = 22 ; Angle BCA = 54 degrees
Step-by-step explanation:
Assuming that this is a rectangle, we can infer that these angles
are supplementary, meaning they add up to 90 degrees.
Therefore we can simply add them together: (3x - 30) + (2x + 10) = 90.
We can simply combine like-terms getting us, 5x - 20 = 90.
We add 20 degrees to both sides and we end up with 5x = 110
degrees. Now we just divide by 5 to get x by itself and we end with
x = 22 degrees. To find either of the angles simply just plug in your x
value. For example, to find angle BCA we just plug x into the equation
leading us to get (2(22) + 10). Now we just multiply and add leading us to
get 54 degrees.
Step-by-step explanation:
Angles at vertices equal 90
so 3x-30+2x +10 = 90
5x-20 =90
x = 110/5 = 22°
m<BCA = 2*22+10 = 44+10 =54°