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A chauffeur drove 28 km, driving the first five minutes at full speed, the next five minutes at half speed, and the third five minutes at quarter speed. What is the full speed of the car? ​

Respuesta :

Step-by-step explanation:

distance = rate X time

5 minutes is 1/12 hr

f = full speed

28 km = f * 1/12   + 1/2 f * 1/12  + 1/4 f * 1/12

28  = f * (1/12 + 1/24 + 1/48)  

28 = f * 7/48

f = 28 * 48/7 = 192 km/hr

Answer:

Full speed = 192 km/h

Step-by-step explanation:

  • Let the speed be v km/h
  • The speeds are given in intervals of 5 minutes starting with the first 5 minutes. Since there are 60 minutes in 1 hour,
    5 minutes = 5/60 hour = 1/12 hour

  • First five minutes(1/12 hour) is driven at full speed which is v km/h
    Distance covered =  v * 1/12 = v/12 km

  • Second 5 minutes is driven at half speed which is v/2 km/h
    Distance covered = v/2 * 1/12 = v/24 km
  • Last 5 minutes is driven at quarter speed which is v/4 km/h

  • Distance covered = v/4 * 1/12 = v/48

  • Total distance covered in terms of v
    = v/12 + v/24 + v/48   [1]

  • LCM of 12, 24 and 48 = 48

  • Multiply each of the individual terms in [1]  by 48/48 to get a common denominator
    [tex]v/12 * 48/48 = v * 4/48 = 4v/48[/tex]

    [tex]v/24 * 48/48 = v * 2/48 = 2v/48[/tex]

    [tex]v/48 * 48/48 = v * 1/48 = 1v/48[/tex]

  • Adding up we get the total distance covered (in terms of v):
    [tex]\dfrac{4v}{48} + \dfrac{2v}{48} + \dfrac{1v}{48} \\\\= \dfrac{4v + 2v + 1v}{48}\\\\= \dfrac{7v}{48}[/tex]

  • We are given the total distance traveled = 28km
    Hence
    [tex]\dfrac{7v}{48} = 28[/tex]

  • Multiply both sides by [tex]\dfrac{48}{7}[/tex]:
    [tex]\dfrac{7v}{48} \cdot \dfrac{48}{7} = 28 \cdot \dfrac{48}{7}[/tex]
    or

    [tex]v = 4 \cdot 48 \\\\v = 192 km/h[/tex]