Answer:
Certainly! Let’s calculate the average force exerted on the bullet.
Given:
Mass of the bullet, (m): 0.030 kg
Final velocity of the bullet, (v): 600 m/s
Time taken for the acceleration, (t): 2.0 ms (which is equivalent to 0.002 seconds)
Calculate the acceleration using the formula: [ a = \frac{{v - u}}{{t}} ] where (u) is the initial velocity (assumed to be 0 m/s since the bullet starts from rest). [ a = \frac{{600 - 0}}{{0.002}} = 300,000 , \text{m/s}^2 ]
Calculate the average force using Newton’s second law: [ F = m \cdot a ] [ F = 0.030 \cdot 300,000 = 9,000 , \text{N} ]
Therefore, the average force exerted on the bullet is 9,000 N.
If you have any more questions or need further assistance, feel free to ask!
Explanation:
