Respuesta :
Answer:
2) 6.03 × 10¹⁴ Hz
Explanation:
We can find the photon's frequency using the Planck's Equation:
[tex]\boxed{E=h\frac{c}{\lambda}=hf }[/tex]
where:
- E = energy of a photon
- h = Planck's constant = 6.625×10⁻³⁴ Js
- c = speed of light = 3×10⁸ m/s
- λ = wavelength
- f = frequency
Given:
E = 2.56 eV
= (2.56 × 1.602×10⁻¹⁹) J
= 4.096×10⁻¹⁹ J
[tex]E=hf[/tex]
[tex]4.096\times10^{-19}=6.625\times10^{-34}\cdot f[/tex]
[tex]\displaystyle f=\frac{4.096\times10^{-19}}{6.625\times10^{-34}}[/tex]
[tex]\displaystyle =\frac{4.096}{6.625} \times10^{(-19+34)}[/tex]
[tex]=0.618\times10^{15}[/tex]
[tex]\approx6.03\times10^{14}\ Hz[/tex]
