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an object is acted on by 2 forces 3N and 5N inclined at 60° to each other. If the object is moved through a distance of 6m by the resultant force, the work done is​

Respuesta :

Answer:

42 J

Explanation:

First find the magnitude of the resultant force. If the 3N force is horizontal, and the 5N force is 60° above horizontal, then the components of the resultant force are:

Fₓ = 3 cos 0° + 5 cos 60° = 5.5 N

Fᵧ = 3 sin 0° + 5 sin 60° = 4.33 N

So the magnitude of the resultant force is:

F² = Fₓ² + Fᵧ²

F² = (5.5 N)² + (4.33 N)²

F = 7 N

The work done is:

W = Fd

W = (7 N) (6 m)

W = 42 J

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