Respuesta :
Answer:
A = 1
B = 5
C can be any digit from 0 to 9
D = 1
E = 5
x = 1
The possibilities for C range from 0 to 9. For each value of C, the equation will hold true. So, the solution set is {(1, 5, C, 1, 5, 1) | C = 0, 1, 2, ..., 9}.
Answer:
A = 1
B = 5
C can be any digit from 0 to 9
D = 1
E = 5
x = 1
The possibilities for C range from 0 to 9. For each value of C, the equation will hold true. So, the solution set is {(1, 5, C, 1, 5, 1) | C = 0, 1, 2, ..., 9}.