Respuesta :

Answer:

A = 1

B = 5

C can be any digit from 0 to 9

D = 1

E = 5

x = 1

The possibilities for C range from 0 to 9. For each value of C, the equation will hold true. So, the solution set is {(1, 5, C, 1, 5, 1) | C = 0, 1, 2, ..., 9}.

Answer:

A = 1

B = 5

C can be any digit from 0 to 9

D = 1

E = 5

x = 1

The possibilities for C range from 0 to 9. For each value of C, the equation will hold true. So, the solution set is {(1, 5, C, 1, 5, 1) | C = 0, 1, 2, ..., 9}.