Answer:
27 cm²
Step-by-step explanation:
You want the area of an isosceles trapezium with bases 5 cm and 13 cm, and slant height 5 cm.
Height
A perpendicular to the long base from one end of the short base will cut off a triangle with side length 4 and hypotenuse 5. The Pythagorean theorem tells you the height of the triangle is ...
h = √(5² -4²) = √9 = 3
Area
The area of the trapezium is given by ...
A = 1/2(b1 +b2)h
A = 1/2(5 cm +13 cm)(3 cm) = 27 cm²
The area of the trapezium is 27 square centimeters.
