Jamie is walking at a speed of 3 m/s. As she goes to cross the street, she sees the crosswalk signal start to countdown, so she hurries and runs across at a speed of 8 m/s. It took her 2 seconds to go from walking to running full speed, what was her rate of acceleration?

Initially, Jamie was walking at a speed of 3 m/s, and then she accelerated to a speed of 8 m/s while crossing the street. So, the change in velocity is:

8 m/s - 3 m/s = 5 m/s

The time taken for this change in velocity is 2 seconds.

Now, we can plug these values into the formula for acceleration:

Acceleration = (5 m/s)/(2 s)

Acceleration = 2.5 m/s²

Jamie’s acceleration was 2.5 m/s².

Learn more about acceleration here: https://brainly.com/question/460763

msm555 msm555 · Answer 2 · 2024-02-17T15:18:19+01:00

Answer:

[tex]2.5 \, \textsf{m/s}^2 [/tex]

Explanation:

Acceleration ([tex]a[/tex]) is defined as the change in velocity per unit time. Mathematically, it is expressed as:

[tex] a = \dfrac{\Delta v}{\Delta t} [/tex]

where:

[tex] \Delta v [/tex] is the change in velocity.
[tex] \Delta t [/tex] is the change in time.

In this scenario, Jamie goes from walking at 3 m/s to running at 8 m/s, so the change in velocity ([tex] \Delta v [/tex]) is [tex]8 \, \textsf{m/s} - 3 \, \textsf{m/s} = 5 \, \textsf{m/s}[/tex].

The change in time ([tex] \Delta t [/tex]) is given as 2 seconds.

Now, substitute these values into the formula:

[tex] a = \dfrac{5 \, \textsf{m/s}}{2 \, \textsf{s}} [/tex]

[tex] a = 2.5 \, \textsf{m/s}^2 [/tex]

Therefore, Jamie's rate of acceleration is [tex]2.5 \, \textsf{m/s}^2[/tex].