Answer:
below is your answer
Explanation:
To find the frequency \( f \) of a photon with a given wavelength \( \lambda \), you can use the formula:
\[ f = \frac{c}{\lambda} \]
where:
- \( f \) is the frequency of the photon,
- \( c \) is the speed of light in vacuum (approximately \( 3.00 \times 10^8 \) meters per second), and
- \( \lambda \) is the wavelength of the photon.
Given that the wavelength \( \lambda \) is \( 781 \) nanometers (\( 781 \times 10^{-9} \) meters), you can plug in the values to find the frequency:
\[ f = \frac{3.00 \times 10^8 \, \text{m/s}}{781 \times 10^{-9} \, \text{m}} \]
\[ f \approx 3.84 \times 10^{14} \, \text{Hz} \]
So, the frequency of a photon with a wavelength of \( 781 \) nm is approximately \( 3.84 \times 10^{14} \) Hz.
Answer:
Explanation:
a frequency of a photon of WL 781 is F.384122.22 hertz pretty easy
