Answer:
Explanation:
To find the mass of barium sulfate produced, we need to use the stoichiometry of the balanced chemical equation and the given masses of the reactants.
The balanced chemical equation is:
3Ba(NO3)2 + Al2(SO4)3 -> 3BaSO4 + 2Al(NO3)3
From the balanced equation, we can see that the ratio of Ba(NO3)2 to BaSO4 is 3:3, and the ratio of Al2(SO4)3 to BaSO4 is 1:3.
1. Calculate the number of moles of Ba(NO3)2:
Molar mass of Ba(NO3)2 = atomic mass of Ba + (atomic mass of N * 2) + (atomic mass of O * 6)
Molar mass of Ba(NO3)2 = 137.33 g/mol + (14.01 g/mol * 2) + (16.00 g/mol * 6)
Molar mass of Ba(NO3)2 = 261.34 g/mol
Number of moles of Ba(NO3)2 = Mass of Ba(NO3)2 / Molar mass of Ba(NO3)2
Number of moles of Ba(NO3)2 = 75 g / 261.34 g/mol
2. Calculate the number of moles of Al2(SO4)3:
Molar mass of Al2(SO4)3 = (atomic mass of Al * 2) + (atomic mass of S + (atomic mass of O * 4) * 3
Molar mass of Al2(SO4)3 = (26.98 g/mol * 2) + (32.07 g/mol + (16.00 g/mol * 4) * 3
Molar mass of Al2(SO4)3 = 342.16 g/mol
Number of moles of Al2(SO4)3 = Mass of Al2(SO4)3 / Molar mass of Al2(SO4)3
Number of moles of Al2(SO4)3 = 50 g / 342.16 g/mol
3. Determine the limiting reactant:
To determine the limiting reactant, compare the number of moles of Ba(NO3)2 and Al2(SO4)3. The reactant with the smaller number of moles is the limiting reactant.
4. Calculate the number of moles of BaSO4 produced:
Using the ratio from the balanced equation, we know that 3 moles of Ba(NO3)2 produce 3 moles of BaSO4.
5. Convert moles of BaSO4 to mass:
Molar mass of BaSO4 = atomic mass of Ba + (atomic mass of S) + (atomic mass of O * 4)
Molar mass of BaSO4 = 137.33 g/mol + 32.07 g/mol + (16.00 g/mol * 4)
Molar mass of BaSO4 = 233.39 g/mol
Mass of BaSO4 = Number of moles of BaSO4 * Molar mass of BaSO4
By following these steps and substituting the values into the calculations, you will be able to determine the mass of barium sulfate produced.
