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I NEED HELP ON THIS BADLY PLEASE!!!! IM GIVING LOTS OF POINTS AND BRAINLIEST!!! This is due today so it would help so so much if someone can help me with this please

I NEED HELP ON THIS BADLY PLEASE IM GIVING LOTS OF POINTS AND BRAINLIEST This is due today so it would help so so much if someone can help me with this please class=

Respuesta :

msm555

Answer:

74

Step-by-step explanation:

Since FH || JM and HJ || MF,

So, the given figure FHJM is a parallelogram.

Given:

  • m∠J = 106°

To find:

  • m∠DAB = ?

Solution:

In this case:

m∠J and m∠H are co interior angle.

Co-interior angles are a pair of non-adjacent interior angles that lie on the same side of a transversal intersecting two parallel lines. In a parallelogram, they are formed by the intersection of the transversal with one side of the parallelogram and an adjacent side.

And;

The sum of co-interior angles in a parallelogram is always 180°

So, we can say that:

m∠F + m∠J = 180°

Substitute the value:

m∠F + 106° = 180°

Subtract 106° on both sides:

m∠F + 106° - 106° = 180° - 106°

m∠F = 74°

Therefore, the answer is 74.