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Charles's Law describes the relationship between the volume and temperature of a gas at constant pressure. If the temperature of a gas is doubled while keeping pressure constant, what happens to its volume?

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Answer:

If the temperature of a gas is doubled while keeping pressure constant, its volume will also double.

Explanation:

According to Charles's Law, at constant pressure, the volume of a gas is directly proportional to its temperature (measured in Kelvin). Mathematically, this relationship is expressed as:

                               [tex]\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \][/tex]

Where:

  • [tex]\( V_1 \) and \( T_1 \)[/tex] are the initial volume and temperature of the gas, respectively.
  • [tex]\( V_2 \) and \( T_2 \)[/tex] are the final volume and temperature of the gas, respectively.

If the temperature of a gas is doubled while keeping the pressure constant, it means that the initial temperature [tex]\(T_1[/tex] becomes [tex]\( 2 \times T_1 \)[/tex]. Let's call this new temperature [tex]\( T_2 \)[/tex].

Using the formula above:

       [tex]\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \][/tex]

       [tex]\[ \frac{V_1}{T_1} = \frac{V_2}{2 \times T_1} \][/tex]

       [tex]\[ V_2 = 2 \times V_1 \][/tex]

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