An oval track is made by enclosing semicircles on each end of a 44 m by 88 m rectangle. Find the area enclosed by the track. Use 3.14 for pi. 44 m 88 m Question content area bottom Part 1 The area enclosed by the track is enter your response here msquared. (Round to the nearest hundredth as needed.)

To find the area enclosed by the track, we need to calculate the sum of the areas of the rectangle and the two semicircles.
1. Start by finding the area of the rectangle: Area of rectangle = length x width = 44 m x 88 m = 3872 m²

2. Next, find the area of one semicircle: The diameter of the semicircle is equal to the width of the rectangle, which is 88 m. Radius of semicircle = diameter/2 = 88 m/2 = 44 m Area of semicircle = (1/2) x π x (radius)^2 = (1/2) x 3.14 x (44 m)^2 = 3038.96 m²

3. Since there are two semicircles, multiply the area of one semicircle by 2: Total area of both semicircles = 2 x 3038.96 m² = 6077.92 m²

4. Finally, add the area of the rectangle and the total area of the semicircles: Total area enclosed by the track = area of rectangle + total area of semicircles Total area = 3872 m² + 6077.92 m² = 9949.92 m²

Therefore, the area enclosed by the track is approximately 9949.92 square meters.

Brainliest pls :P

mathstudent55 mathstudent55 · Answer 2 · 2024-02-12T23:37:12+01:00

mathstudent55 mathstudent55

12-02-2024

Answer:

5391.76 m²

Step-by-step explanation:

area of rectangle = LW = 44 m × 88 m = 3872 m²

The two semicircles are the short sides add to a circle. The diameter is 44 m, so the radius is 22 m.

area of circle = πr² = 3.14 × (22 m)² = 1519.76

total area = 3872 m² + 1519.76 m² = 5391.76 m²

Answer Link