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Hotdogs and corndogs were sold at last night's football game. The number of hotdogs sold was three fewer than twice the number of corndogs. A hotdog costs $3 and a corndog costs $1.50. $201 was collected. How many hot dogs and corndogs were sold?

Respuesta :

Answer:

Step-by-step explanation:

H=Hotdog

C=Corndog

The number of hotdogs sold was three fewer than twice the number of corndogs. This can be written as:

h = 2c - 3

hotdog costs $3 and a corndog costs $1.50. The total amount collected from selling hotdogs and corndogs is $201. Said as:

3h + 1.5c = 201

Now we have a system of equations:

h = 2c - 3

3h + 1.5c = 201

To solve this system, we can use the substitution method. We can solve the first equation for "h" in terms of "c" and substitute it into the second equation:

h = 2c - 3

3(2c - 3) + 1.5c = 201

Simplifying the equation:

6c - 9 + 1.5c = 201

7.5c - 9 = 201

7.5c = 210

c = 210 / 7.5

c = 28

Now we can substitute the value of "c" back into the first equation to find the value of "h":

h = 2(28) - 3

h = 56 - 3

h = 53

Therefore, 53 hotdogs and 28 corndogs were sold at last night's football game.