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Which sequence could be used to prove that AD = BC?

First prove TriangleABC is congruent to TriangleCDA, and then state AD and BC are corresponding sides of the triangles.
First prove TriangleABC is similar to TriangleCDA, and then state AD and BC are opposite sides of the parallelograms.
First prove ParallelogramABCD is congruent to ParallelogramCDAB, and then state AD and BC are corresponding sides of two parallelograms.
First prove ParallelogramABCD is similar to ParallelogramCDAB, and then state AD and BC are opposite sides of the parallelograms.

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Answer:

First, prove ParallelogramABCD is congruent to ParallelogramCDAB, and then state AD and BC are corresponding sides of two parallelograms.

Step-by-step explanation:

The correct sequence to prove that AD = BC is:

First, prove ParallelogramABCD is congruent to ParallelogramCDAB, and then state AD and BC are corresponding sides of two parallelograms.

This sequence is appropriate because if two parallelograms are congruent, then their corresponding sides are equal in length. Therefore, if Parallelogram ABCD is congruent to Parallelogram CDAB, then AD =

BC, as they are corresponding sides of the parallelograms.

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