Respuesta :
Based from the given information, the maximum amount of solute a 100 g of water can dissolve at 40 degrees Celsius is 15 g of potassium sulfate, K2SO4. The ratio of which 15 g K2SO4/100 g H2O is equal to 0.15. A solution consisting of 39 g K2SO4 per 225 g H2O results to a solubility of 0.173. This is greater than the maximum amount of solute that can be dissolved at the given temperature of 40 degrees Celsius. This means that the resulting solution is supersaturated. It should also be noted that supersaturated solutions are usually prepared by heating the solution in order to dissolve the remaining solute then consequently cooling the solution to the desired temperature.
To determine the amount of K2SO4 precipitated out, use the formula:
(39 - x) g K2SO4/ 225 g H2O = 15 g K2SO4/ 100 g H2O
where, x is the grams of K2SO4 that would crystallize out. After applying the formula, we obtain 5.25 g of potassium sulfate crystals.
To determine the amount of K2SO4 precipitated out, use the formula:
(39 - x) g K2SO4/ 225 g H2O = 15 g K2SO4/ 100 g H2O
where, x is the grams of K2SO4 that would crystallize out. After applying the formula, we obtain 5.25 g of potassium sulfate crystals.
Explanation:
Solubility of potassium sulfate at 40 °C = 15 g/100 g
This means that at 40 °C 15 g of potassium sulfate will get completely dissolved in 100 of water.
39.0 g of potassium sulfate to 225 g water, carefully heating the solution.
Amount of potassium sulfate will get dissolve in 225 g of water at 40 °C will be:
[tex]\frac{15 g}{100 g}\times 225=33.75 g[/tex]
Amount of potassium sulfate precipitated out by the solution:
= 39.0 g-33.75 g = 5.25 g
At 40 °C 5.25 g of potassium sulfate will get precipitate out from the solution which means that solution is saturated.
Saturated solution are solution in which solute is dissolved in maximum amount. Further addition of solute results in precipitation of solute form the solution.
5.25 grams of potassium sulfate will get crystallize out.