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apologiabiology
assuming your expression is this one: [tex]\frac{\sqrt{28(x-1)}}{\sqrt{8x^2}}[/tex]
we won't simplify even though we can

we can't take the square root of negative numbers nor can we divide by 0

so solve for the values that do that

ok, so the square root bits

we got √(28(x-1))
28(x-1)
this can't equal a negative
so when will it be negative?
28(x-1)<0
x-1<0
x<1
at x<1
so values less than 1 are restricted

other square root
√(8x²)
8x²<0
false


ok, and no dividing by 0

set √(8x²)=0
that is at x=0


so our restricted values are x<1 and x=0
so basically x<1 is all restricted values
so x≥1 is the set of all values that make it defined

The inequality represents all values of x for which the quotient below is defined and will be,[tex]\rm \frac{\sqrt{28(x-1)} }{\sqrt{8x^2} }[/tex].

What is the definition of inequality?

Inequality is a sort of equation in which the equal sign is missing. As we will see, inequality is defined as a statement regarding the relative magnitude of two claims.

The given inequality is:

28(x-1)≥0

8x²≥0

It is found that x≥1

The inequality represents all values of x for which the quotient below is defined and will be,[tex]\rm \frac{\sqrt{28(x-1)} }{\sqrt{8x^2} }[/tex].

Hence option C is correct.

To learn more about inequity, refer to https://brainly.com/question/20383699.

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