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Find the x-intercept of the parabola with vertex (-1,-108) and y- intercept (0,-105). write answer in (x1,y1) (x2,y2) form.

I use the formula
y=a(x-h)^2+k
but this one is not making sense to me

Find the xintercept of the parabola with vertex 1108 and y intercept 0105 write answer in x1y1 x2y2 form I use the formula yaxh2k but this one is not making sen class=

Respuesta :

the vertex form is 

f(x) = a(x - (-1))^2 -  108  = a(x + 1)^2 - 108   where a is some constant.
from the y intercept x = 0 when f(x) = -105, so substituting:-

-105  = a (0+1)^2 - 108
a =  -105+108 = 3

so our equation is f(x) = 3(x + 1)^2 - 108

for x intercept:-

3(x +1)^2 - 108 = 0
(x + 1)^2 =  108 / 3 = 36

x+ 1 =  +/- sqrt36  = +/- 6

x =  -7 or 5 
so the x intercepts are at ( (-7,0) and (5,0)

gorraricardezju
Hello My Melo Friend!

The Vertex form = 

[tex]f(x) = a(x - (-1))^2 - 108 = a(x + 1)^2 - 108[/tex]   where A is some constant.
From the y intercept [tex]x = 0[/tex] when [tex]f(x) = -105[/tex], so substituting:-

[tex]-105 = a (0+1)^2 - 108[/tex]
[tex]a = -105+108 = 3[/tex]

So therefore, our equation = [tex]f(x) = 3(x + 1)^2 - 108[/tex]

And For x intercept:-

[tex]3(x +1)^2 - 108 = 0[/tex]
[tex](x + 1)^2 = 108 / 3 = 36[/tex]

[tex]x+ 1 = +/- sqrt36 = +/- 6[/tex]

[tex]x = -7 or 5 [/tex]

So Therefore, as we can clearly see, the x intercepts !SHOULD! be at [tex]( (-7,0) and (5,0)[/tex].

I Hope my answer has come to your Help. Thank you for posting your question here in [tex]Brainly.[/tex] We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)

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