Use the equation for uniform acceleration:
distance = Vo*t + a * t^2 / 2
As the car is initially at rest, Vo = 0
=> distance = a * t^2 / 2.
Now solve for a and replace the data of time and distance:
a = 2 * distance / (t^2)
a = 2 * 120m / (6.32s)^2 = 240m / 39.9424 s^2 = 6.009 m/s^2
Which approximates to 6 m/s^2.
So, the answer is the option B.) 6 meters / second^2