In how many different ways can a team of 3 boys and 2 girls be formed if there are 4 boys and 5 girls from which to select and Robert (one of the boys) must be on the team?

Respuesta :

The selection of k object out of n, is done is C(n, k) many ways,

where, [tex]C(n, k)= \frac{n!}{k!(n-k)!} [/tex]

For example, 

the selection of 2 objects out of 3, can be done in:

[tex]C(3, 2)= \frac{3!}{2!1!}= \frac{3*2*1}{2*1}=3 [/tex] many ways.

another example, 

the selection of 2 objects out of 5 can be done in:

[tex]C(5,2)= \frac{5!}{2!3!}= \frac{5*4*3!}{2!*3!}= \frac{5*4}{2}=10 [/tex]

many ways.


back to our example, 

there are C(3,2)=3 ways of selecting 2 boys out of 3, to form the 3 boys group together with Robert.

There are C(5,2)=10 many ways to select 2 girls out of 5.

Since any selection of the girls and boys can be combined, we have 3*10=30 different ways of forming the groups.


Answer: 30