Respuesta :
Hey!
First, let's write the problem.
[tex]y^2+10z-10y-yz[/tex]
First, we have to factor the y from [tex]y^2-10y[/tex], so we would be left with,
[tex]y\left(y-10\right)[/tex]
Next, we factor the [tex]-z[/tex] from [tex]10z-yz[/tex]. This would leave us with,
[tex]=y\left(y-10\right)-z\left(y-10\right)[/tex]
The common term is [tex]\left(y-10\right)[/tex], so let's factor it out.
[tex]=\left(y-10\right)\left(y-z\right)[/tex]
That would be our final answer.
Thanks!
-TetraFish
First, let's write the problem.
[tex]y^2+10z-10y-yz[/tex]
First, we have to factor the y from [tex]y^2-10y[/tex], so we would be left with,
[tex]y\left(y-10\right)[/tex]
Next, we factor the [tex]-z[/tex] from [tex]10z-yz[/tex]. This would leave us with,
[tex]=y\left(y-10\right)-z\left(y-10\right)[/tex]
The common term is [tex]\left(y-10\right)[/tex], so let's factor it out.
[tex]=\left(y-10\right)\left(y-z\right)[/tex]
That would be our final answer.
Thanks!
-TetraFish
Factor by grouping.
GCF of y^2 and -yz
GCF of 10z and -10y
y(y-z)+10(z-y)
Now, (z-y) is the opposite of (y-z), so turn the +10 into -10 and change sign inside parenthesis.
y(y-z) - 10 (y-z)
(y-10)(y-z)
GCF of y^2 and -yz
GCF of 10z and -10y
y(y-z)+10(z-y)
Now, (z-y) is the opposite of (y-z), so turn the +10 into -10 and change sign inside parenthesis.
y(y-z) - 10 (y-z)
(y-10)(y-z)
