Answer:
The value of function at x = 2 is 8.
Step-by-step explanation:
Given : Function [tex]f(x)=2x^2+5\sqrt{x-2}[/tex]
We have to find the value of given function at x = 2 , that is f(2)
Consider the given function [tex]f(x)=2x^2+5\sqrt{x-2}[/tex]
To find the value f(2) put x = 2 in given function ,
We have,
[tex]f(2)=2(2)^2+5\sqrt{2-2}[/tex]
Simplify, we have,
[tex]f(2)=8+5\sqrt{0}[/tex]
Simplify further, we have,
[tex]f(2)=8[/tex]
Thus, the value of function at x = 2 is 8.
