The height of the building is [tex]50\sqrt{3}[/tex] and it can be determine by using trignometry function.
Given :
To determine the height of the building, trignometric function can be used. [tex]\rm tan\theta[/tex] is one of the important trignometry function and it is equal to the ratio of the perpendicular to the base.
[tex]\rm tan\theta = \dfrac{Perpendicular}{Base}[/tex]
Given that the base is 50 feet and [tex]\theta[/tex] is [tex]60^\circ[/tex]. So, put the value of base and [tex]\theta[/tex] in above equation we get the height of the building.
[tex]\rm tan60^\circ = \dfrac{Height \; of \;the \; Building}{50}[/tex]
Now, put the value of [tex]\rm tan60^\circ[/tex] which is [tex]\sqrt{3}[/tex] in the above equation.
[tex]\rm \sqrt{3} = \dfrac{Height \; of \;the \; Building}{50}[/tex]
[tex]\rm 50\sqrt{3} = Height \; of \;the \; Building[/tex]
Therefore, the height of the building is [tex]50\sqrt{3}[/tex].
For more information, refer the link given below
https://brainly.com/question/17081568
