original height = original width = x mm
1. She made an enlarged copy...
height = 2x
width = 2x
2. She cut off a rectangle...
height = 2x
width = [tex] \frac{2}{3} *2x= \frac{4}{3}x [/tex]
3.She doubled the width...
height = 2x
width = [tex]2*\frac{4}{3}x = \frac{8}{3}x [/tex]
height * width = area
[tex]2x * \frac{8}{3}x=139 \ 968 \\ \\ \frac{16}{3}x^2= 139 \ 968 \\\\ x^2=139 \ 968: \frac{16}{3}=139 \ 968 * \frac{3}{16}= 8 \ 748*3 = 26 \ 244 \\ \\ x= \sqrt{26 \ 244} = 162 \ mm [/tex]
Original height was 162 mm
