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What are the exact solutions of x^2 = 4 − 7x? x = x equals negative 7 plus or minus the square root of thirty-three all over 2 x = x equals negative 7 plus or minus the square root of sixty-five all over 2 x = x equals 7 plus or minus the square root of sixty-five all over 2 x = x equals 7 plus or minus the square root of thirty-three all over 2

Respuesta :

x equals negative 7 plus or minus the square root of 65 all over 2
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Answer:

(B) x equals negative 7 plus or minus the square root of sixty-five all over 2

Step-by-step explanation:

The given equation is:

[tex]x^2=4-7x[/tex]

Simplifying the above equation, we have

[tex]x^2+7x-4=0[/tex]

Using the Quadratic formula, we get

[tex]x=\frac{-7{\pm}\sqrt{(7)^2-4(1)(-4)}}{2}[/tex]

[tex]x=\frac{-7{\pm}\sqrt{49+16}}{2}[/tex]

[tex]x=\frac{-7{\pm}\sqrt{65}}{2}[/tex]

Hence, the exact solution of the given equation is x equals negative 7 plus or minus the square root of sixty-five all over 2.

Therefore, option (B) is correct.

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