polancomarina
contestada

The slope-intercept form of the equation of a line that passes through point (–3, 8) is y = –2/3x + 6. What is the point-slope form of the equation for this line?

y – 3 = –2/3(x + 8)
y + 3 = –2/3(x – 8)
y + 8 = –2/3(x – 3)
y – 8 = –2/3(x + 3)

Respuesta :

texaschic101
y = -2/3x + 6....the slope here is -2/3

y - y1 = m(x - x1)
slope(m) = -2/3
(-3,8)....x1 = -3 and y1 = 8
now we sub
y - 8 = -2/3(x - (-3) =
y - 8 = -2/3(x + 3) <===

Cetacea

The point-slope form of the equation for this line is: [tex]y-8=-\frac{2}{3}\left(x+3\right)[/tex]

The given point is = (-3, 8).

Compare the slope intercept form [tex]y=-\frac{2}{3}x+6[/tex] with y = mx+b

So, slope = m = [tex]-\frac{2}{3}[/tex].

So, the point-slope form of the equation for this line is:

[tex]y-y_{1}=m\left(x-x_{1}\right)\\y-8=-\frac{2}{3}\left(x-\left(-3\right)\right)\\y-8=-\frac{2}{3}\left(x+3\right)[/tex]

Learn more: https://brainly.com/question/21022674