If a quadrilateral is a rhombus then:
i) all its sides have equal length,
and
ii) the 2 diagonals are perpendicular and bisect each other.
The 2 diagonals of rhombus JKLM intersect at N.
Then m(MNJ)=90°, |JN|=4 and |NM|=3 units
thus, by the Pythagorean theorem,
[tex]|MJ|= \sqrt{ 3^{2} + 4^{2} }= \sqrt{9+16}= \sqrt{25}=5[/tex]
The perimeter of the rhombus is 4*5 units=20 units.
Answer: 20 units
