Respuesta :
The scores of Alexandria are 82, 77, 81, 74 and x, the score of the last test.
the average of these 5 is [tex] \frac{82+77+81+74+x}{5}= \frac{314+x}{5} [/tex],
to get a b, the average must be at least 80.
So,
[tex]\frac{314+x}{5} =80[/tex]
314+x=400
x=400-314 = 86
Thus, to get a B, Alexandria must score at least 86 on her last test.
Answer: 86
the average of these 5 is [tex] \frac{82+77+81+74+x}{5}= \frac{314+x}{5} [/tex],
to get a b, the average must be at least 80.
So,
[tex]\frac{314+x}{5} =80[/tex]
314+x=400
x=400-314 = 86
Thus, to get a B, Alexandria must score at least 86 on her last test.
Answer: 86
The answer to your question is 86, hope this helped!