Yesenialopez264
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Two urns contain white balls and yellow balls. The first urn contains 3 white balls and 6 yellow balls and the second urn contains 7 white balls and 3 yellow balls. A ball is drawn at random from each urn. What is the probability that both balls are white?

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1234cordelianaranjo
so in the first urn, there are 9 balls total. and out of those 9, 3 are white, so that would be 1/3. you would have 1/3 of a chance out of that urn


the second urn has 10 balls in it. out of all the balls, there are 7 white ones, so the chances of drawing from that one a white is 7/10.


now the chances of getting both white are hard to find. you have 19 balls altogether, and 10 are white. so this means there is a 10/19 chance you will draw a white from ONE. but from both, you have about 36% chance.



im not 100% sure about the answer, but I do know the other part. hope this helps explain it at least!

Answer:  

[tex]\text{So, The probability that both balls are white = }\frac{7}{30}[/tex]

Step-by-step explanation:

Number of white balls in the first urn = 3

Number of yellow balls in the firs urn = 6

[tex]\text{Probability of selecting the white ball from first urn = }\frac{3}{9}[/tex]

Number of white balls in the second urn = 7

Number of yellow balls in the second urn = 3

[tex]\text{Probability of selecting the white ball from second urn = }\frac{7}{10}[/tex]

Now, we need to find the probability that both balls are white

[tex]\text{So, The probability that both balls are white = }\frac{3}{9}\times \frac{7}{10}=\frac{7}{30}[/tex]

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