Answer:
[tex]a =-153.6\ m/s^{2}[/tex]
Explanation:
Since we are assuming that is acceleration in water is constant, we are going to use one of the uniform accelerated motion formulas. Since we know the initial velocity ([tex]v_{0}=43 m/s[/tex]), the final velocity ([tex]v_f=0[/tex]) and, the time it takes to stop ([tex]t=0.28s[/tex]) so, we are going to use:
[tex]v_{f}=v_{0}+at[/tex],
where a is the acceleration.
Solving for the acceleration
[tex]a=\dfrac{v_{f}-v_{0}}{t}[/tex]
and, computing
[tex]a =\dfrac{0-43}{0.28}\\\\a=-153.6\ m/s^{2}[/tex].
Notice that the acceleration is negative. This is because the speed decreases when the hailstone enters the water.
