The diameter of a large lawn ornament in the shape of a sphere is 16 inches. What is the approximate volume of the ornament? Use 3.14 for π . Round to the nearest tenth of a cubic inch.

Respuesta :

Answer: [tex]2143.6\ in.^3[/tex]

Step-by-step explanation:

Given: The diameter of a large lawn ornament in the shape of a sphere = 16 inches.

Then, the radius of ornament =[tex]\frac{16}{2}=8[/tex] inches.

We know that the volume of a sphere is given by :-

[tex]\text{Volume}=\frac{4}{3}\pi r^3[/tex], where r is the radius of a sphere.

Now, the volume of the ornament is given by :-

[tex]\text{Volume}=\frac{4}{3}(3.14) (8)^3\\\\\Rightarrow\text{Volume}=\frac{4}{3}\times3.14\times512=2143.57333333\approx2143.6\ in,^3[/tex]

Hence, the approximate volume of the ornament [tex]=2143.6\ in.^3[/tex]

The sphere a round solid shape. The approximate volume of the ornament is 2,143.6 cubic in

How to calculate the volume of a sphere?

The formula for calculating the volume of sphere is expressed as:

V = 4/3 πr^3

r is the radius = 8in

Substitute

V = 4/3* 3.14 * 8^3

V = 6,430.72/3

V = 2,143.57 cubic in

Hence the approximate volume of the ornament is 2,143.6 cubic in

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