Respuesta :
Use Einstein's famous equation:
[tex]E = mc^2[/tex]
where, c=speed of light
m = mass defect = 1.908 g/mol = 1.908 x 10^{-3} kg/mol
E = Binding energy
So, E = [tex]1.908 \times 10^{-3} \times (3 \times 10^8)^2[/tex]
[tex]E = 5.724 \times 10^{13} J[/tex]
[tex]E = mc^2[/tex]
where, c=speed of light
m = mass defect = 1.908 g/mol = 1.908 x 10^{-3} kg/mol
E = Binding energy
So, E = [tex]1.908 \times 10^{-3} \times (3 \times 10^8)^2[/tex]
[tex]E = 5.724 \times 10^{13} J[/tex]
Answer: The binding energy of one mole of thorium atom is [tex]17.172\times 10^{13}J[/tex]
Explanation:
Binding energy is defined as the energy which holds the nucleus together. It is basically the product of mass defect and the square of the speed of light.
This energy is calculated by using Einstein's equation, which is:
[tex]E=\Delta mc^2[/tex]
Where,
E = Binding energy of the atom
[tex]\Delta m[/tex] = Mass defect = 1.908 g/mol = [tex]1.908\times 10^{-3}kg/mol[/tex] (Conversion factor: 1 kg = 1000 g)
c = speed of light = [tex]3\times 10^8m/s[/tex]
Putting values in above equation, we get:
[tex]E=1.908\times 10^{-3}kg/mol\times (3\times 10^8m/s)^2=17.172\times 10^{13}J/mol[/tex]
Hence, the binding energy of one mole of thorium atom is [tex]17.172\times 10^{13}J[/tex]