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A ball of radius 13 has a round hole of radius 6 drilled through its center. find the volume of the resulting solid.

Respuesta :

The radius of the ball is 13 units.
Its volume is
V₁ = (4π*13³)/3
     = 9.2028 x 10³ units³

The drilled hole has the approximate shape of a solid cylinder with radius = 6 and length = 26. Its volume is
V₂ = π*(6²)*26
     = 2.9405 x 10³ units³

The volume of the resulting solid is
V₁ - V₂ = 6.2622 x 10³

Answer: 6.2622 x 10³  units³

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