The vapor pressure of water at 20oC is 17.5 torr. Calculate the vapor pressure of an aqueous solution prepared by adding 36.0 g of glucose (C6H12O6) to 14.4 g of water.

Respuesta :

Answer:

14.0075torr

Explanation:

to calculate the vapor pressure we use Roault's law (the vapour pressure of a solvent above a solution is directly proportional to the mole fraction of the solvent in the solution)

so

the more fraction of water = 0.801

the mole fraction of glucose =0.199

next calculate the total moles of solute and solvent in solution, which is 0.998mol

vapour pressure of water 20°C =17.5torr

vapour pressure of solution=

mole fraction of water × vapour pressure of water

=0.801×17.5torr

vapour pressure of solution= 14.0075torr

(36.0g of glucose to 14.4g of water is approximately 14.0075torr)