Answer :
- 5x^2 - 6x + 1 = 0
- x = 1 or 1/5
Explanation :
the standard form of a quadratic equation is given by ,
thus, the standard version of the equation given would be,
- 5x^2-6x-9=-10
- 5x^2 - 6x - 9 + 10 = 0
- 5x^2 - 6x + 1 = 0
we can further find the value of x or roots of the equation using the quadratic formula which is given by,
- x = (- b ±√(b^2 - 4ac))/2a
plugging in the values of the variables
we get
- x = (-(-6) ±√((-6)^2 -4*5*1))/2*5
- x = (6 ±√(36 -20))/10
- x = (6 ±√(16))/10
- x = (6 + 4)/10 = 10/10 = 1
- x = (6 - 4)/10 = 2/10 = 1/5
thus ,the value of x is either 1 or 1/5 .
